![]() ![]() Which is consistent with the cut-off text at the bottom. This immediately brings DnD to mind, but looking at the relevant xkcd's alt text, I think a different version is used here: The writing direction is left to right, and many of the symbols look like Roman alphabet letters. It is more than 240 pages long, but some of the pages are missing. Which is again Old English, meaning "The guide to playing a game of worlds and fairytales/stories". Answer: The Voynich manuscript is made of vellum, a kind of parchment, and has been carbon-dated to around 1400 AD, medieval times. "se regol to gamenan se gamen mid eardgeardas and ealdspell" "dm ymzjv kj zoamioi dm zoami apq moyqzmoyqod oiq movqdxmvv" This string contains every letter exactly once, suggesting a map to the alphabet, or substitution cipher:Īnd we can use that cipher to decode the very last message: Proceeding similarly for the other sets of stars in the text (through a combination of Mathematica and tedious manual labor) gives us a 26-letter string: Which, when connected, give the letter N. ![]() For example, the last set of stars:Ĭorresponds to these stars in the diagram: It turns out that everything other than the first and last lines here is not encoded latin characters, but actual names of stars from the manuscript. For example, some people say that trying to crack the Voynich Manuscript is not unlike attempting to solve a million-piece jigsaw with your eyes shut: but some. The OP says "It fell out of page f68r1.", which is one of a few 'star guides' in the manuscript. The last line seems to be a different cipher from the rest of the text, which would make sense as it is also a separate image in the OP. "Seon heofonsteorran" is Old English, meaning (roughly) "See the stars". I'm sure you can see patterns in there already, but first and last lines of that especially look very different from the rest, so let's focus on those: Part of the key hints is placed on the sheet 14. The key to the cipher manuscript placed in the manuscript. There is a key to cipher the Voynich manuscript. I am deciphering the Voynich manuscript and received a positive result. Okcor ofcheor ykchdy qoeeodcey otcedo ofcheorĭm ymzjv kj zoamioi dm zoami apq moyqzmoyqod oiq movqdxmvv Your site has information about the Voynich manuscript. Okcor ofcheor ykchdy ofcheor cpeoekhy ofcheor otcedo Okialy chocfez cpeoekhy chocfez okcor oekey olorĬhocfez okcor ofcheor otcedo ofcheor ykchdy qoeeodcey Olor oekey okcor chocfez okialy otydy okcorĬpeoekhy chocfez okcor ofcheor cpeoekhy otcedo When we do that, we get a pretty big chunk of text: The linked Wikipedia page, which gives a rather enticing way of converting from symbols to Latin characters in this picture: The characters in the OP are (pretty much) consistently written, so I made a Mathematica program to split the OP into its letters and then see what Latin character it corresponds to. ![]() Our first clue in this puzzle comes from: I'm not sure if it's customary to post code here or not, so for now I will leave it out, but if anyone wants to see how I did it I'll be happy to update. ![]()
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